4.1x^2+2.2x-8.9=0

Solution for 4.1x^2+2.2x-8.9=0 equation:

4.1x^2+2.2x-8.9=0

a = 4.1; b = 2.2; c = -8.9;
Δ = b2-4ac
Δ = 2.22-4·4.1·(-8.9)
Δ = 150.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.2)-\sqrt{150.8}}{2*4.1}=\frac{-2.2-\sqrt{150.8}}{8.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.2)+\sqrt{150.8}}{2*4.1}=\frac{-2.2+\sqrt{150.8}}{8.2}
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